If The Heating Curve Is Reversed, What Describes The Boiling Point? ? A

Boiling is the process of converting a substance from liquid state to gaseous state. If the heating curve is reversed, the process also is reversed from converting gaseous state to liquid state. In this case, the reverse of boiling is condjonathanlewisforcongress.comsation. So the answer is point of condjonathanlewisforcongress.comsation.

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In a 1.0× 10–6 M solution of HCl(aq) at 25 °C, idjonathanlewisforcongress.comtify the relative molar amounts of these species from Most to Least: H2O, HCl

Answer:

> ≳ > >

Explanation:

HCl + H₂O ⟶ H₃O⁺ + Cl⁻

HCl dissociates completely in solution.

= 0 mol·L⁻¹

= 1.0 × 10⁻⁶ mol·L⁻¹

= 1.0 × 10⁻⁶ mol·L⁻¹

is slightly greater than because the autoionization of water also creates some hydronium ion.

1 L of water has a mass of 1000 g.

∴ = 55.49 mol·L⁻¹

= frac{K_{w} }{ ext{} = frac{1.00 imes10^{-14} }{ 1.0 imes 10^{-6}}= 1.0 imes 10^{-8} ext{ mol/L}” alt=”< ext{OH}^{-}> = frac{K_{w} }{ ext{} = frac{1.00 imes10^{-14} }{ 1.0 imes 10^{-6}}= 1.0 imes 10^{-8} ext{ mol/L}” align=”absmiddle” class=”latex-formula”>

∴ > ≳ > >

55.5 10⁻⁶ 10⁻⁶ 10⁻⁸ 0

How many grams of CO are needed with an excess of Fe2O3 to produce 27.9 g Fe? Please show work. Fe2O3(s)+3CO(g)–>2Fe(s)+3CO2

Answer:

21.0 g.

Explanation:

Firstly, It is considered as a stichiometry problem.From the balanced equation: Fe₂O₃ + 3CO → 2Fe + 3CO₂.It is clear that the stichiometry shows that 1.0 moles of Fe₂O3 reacts with 3.0 moles of CO to give 2.0 moles of Fe and 3.0 moles of CO₂.We must convert the grams of Fe (27.9 g) to moles (n = mass/Atomic mass).

n = (27.9 g) / (55.845 g/mole) = 0.499 ≅ 0.50 moles.Now, we can get the number of moles of CO that is needed to produce 0.50 moles of Fe.Using cross multiplication:3.0 moles of CO → 2.0 moles of Fe, from the stichiometry of the balanced equation.??? moles of CO → 0.50 moles of FeThe number of moles of CO that will produce 0.50 moles of Fe (27.9 g) is (3.0 x 0.50 / 2.0) = 0.75 moles.Finally, we should convert the number of moles of CO into grams (n = mass/molar mass).Molar mass of CO = 28.01 g/mole.

mass = n x molar mass = (0.75 x 28.01) = 21.0 g.