Let X represent the difference between the number of heads and the number of tails when a coin is tossed 32 times. Then P(X=12)
Work :
Let H be the number of Heads & T be the number of Tails.
You are watching: Let x represent the difference between the number of heads and the number of tails
We want P(|H-T| = 12)
We have T = 32-H so,
P (|H-T| = 12 ) = P ( |H-32+H | = 12 )
= P ( |2H-32 | = 12 )
= P (2H-32 = 12 or 2H-32 = -12)
=P (H = 22 or H = 10)
= (32 C 22 )(0.5)^32 + (32 C 10 )(0.5)^32
= 0.0300
Am I doing correct or wrong?
Thank you in advance..
Alpha agrees with you to the places you gave. Note that ${32 choose 22}={32 choose 10}$ so I did just one and removed one factor of $frac 12$
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