What are the oxidation states for all of the elements in AlCl3? What are the oxidation states for all of the elements in AlCl3?A –1, +1 B –3, +3 C +1, –1 D +3, –3
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`AlCl_3`
Aluminium Al oxidation state = +3
Aluminium atomic number = 13
Electronic Configuration = `1s^2 2s^2 2p^6 3s^2 3p^1` ` `
It loses 3 electrons from `3s^2` and `3p^1` and form +3 oxidation state.
Chlorine Cl oxidation state = -1
Atomic number = 17
Electronic Configuration = `1s^2 2s^2 2p^6 3s^2…
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`AlCl_3`
Aluminium Al oxidation state = +3
Aluminium atomic number = 13
Electronic Configuration = `1s^2 2s^2 2p^6 3s^2 3p^1` ` `
It loses 3 electrons from `3s^2` and `3p^1` and form +3 oxidation state.
Chlorine Cl oxidation state = -1
Atomic number = 17
Electronic Configuration = `1s^2 2s^2 2p^6 3s^2 3p^5`
It gains 1 electron and form -1 oxidation state.
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The 3 electrons lost by Al is accepted by 3 Cl atom each.
Thus forming `AlCl_3`
Therefore the oxidation states are +3 and -1.
Since its not in options we can consider option D as answer assuming that….
3 electrons lost by Al atom and 3 electrons accepted by Cl atoms.
Thus option D +3, -3 is our answer.
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